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Radius of Gyration of an Area


Equations
(Eq1)    
kx
Ix
A
radius of gyration of an area with respect to the x-axis
(Eq2)    
ky
Iy
A
radius of gyration of an area with respect to the y-axis
(Eq3)    
kO
JO
A
radius of gyration of an area about the origin
(Eq4)    
kO2 = kx2 + ky2
equation relating radii of gyration


Nomenclature
Ixmoment of inertia with respect to the x-axis
Iymoment of inertia with respect to the y-axis
JOpolar moment of inertia
Aarea


Details

Consider an area A which has a moment of inertia Ix with respect to the x-axis as shown.



Imagine that the area is concentrated into a thin strip parallel to the x-axis as shown:



If the area A, thus concentrated, is to have the same moment of inertia with respect to the x-axis, the strip should be placed at a distance kx from the x-axis, where kx is defined by the relation:

Ix = kx2A

Solving for kx:

(Eq1)    
kx
Ix
A

The distance kx is referred to as the radius of gyration of the area with respect to the x-axis. In a similar way, the radii of gyration ky and kO can be defined. The following image represents an area with the same moment of inertia with respect to the y-axis:



For ky :

Iy = ky2A

Solving for ky :

(Eq2)    
ky
Iy
A

Following is an image of a circular area centered about the x- and y-axes that has the same moment of inertia with respect to the x- and y-axes:



Similarly, for JO :

JO = kO2A

Solving for kO :

(Eq3)    
kO
JO
A

If Eq2 from the Polar Moment of Inertia lesson is rewritten in terms of the radii of gyration, it is found that:

(Eq4)    
kO2 = kx2 + ky2




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The material and content of Engineering Archives is designed to be subject to change and alteration at all times. Therefore, it may not be assumed that any presented material herein is static. The material is constantly subject to change for the purpose of maximizing the ability of the learner to comprehend and absorb the material. The changing and alteration is conducted based on user feedback. Therefore, effective changes cannot take place without the user feedback. Please go to the forum for questions and feedback. See more…
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