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Impulse and Momentum, One Dimensional

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Problem
A 0.17 kg hockey puck is moving on an icy, frictionless, horizontal surface. At t = 0 the puck is moving to the right at 5 m/s. a) Calculate the velocity of the puck (magnitude and direction) after a force of 20 N directed to the right has been applied for 0.07 s. b) If instead a force of 35 N directed to the left is applied for t = 0.03 s, what is the final velocity of the puck?

Solution
use the impulse momentum equation and then:

20(0.07) = 0.17(v₂ − 5)

then

v₂ = 13.2 m/s right

b.)
−35(0.03) = 0.17(v₂ − 5)

so

v₂ = −1.18

or:

v₂ = 1.18 m/s to the left